Question

show that (x+2) is a factor of p(x) =x^3 + 4x^2 + x -6 .



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Answer 1

Answer:

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Answer 2

Answer & Step-by-step explanation:

p(x) = x³ + 4x² + x - 6

g(x) = x + 2

Put g(x) = 0 to find its zero.

x + 2 = 0

(x = -2)

Put x = -2 in p(x) to find remainder by REMAINDER THEOREM,

p(-2) = (-2)³ + 4(-2)² + (-2) - 6

        = -8 + 8 - 2 - 6

        = -8

∴ Remainder ≠ 0,

⇒ g(x) is not a factor of p(x).