Show that (x-2) is a factor of polynomial f(x)=2x^3-3x^2-17
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Answered by
1
zero of x - 2 is 2
f(x) = 2x^3 - 3x^2 - 17
f(2) = 2×2^3 - 3×2^2 -17
=16-12-17
=16- 29
= -13
it is not factor.....
f(x) = 2x^3 - 3x^2 - 17
f(2) = 2×2^3 - 3×2^2 -17
=16-12-17
=16- 29
= -13
it is not factor.....
Answered by
3
Zero of x-2=0
f(x)= 2x^3 -3x^2-17
f(2)= 2x2 ^3 - 3x2^2 -17
16-12-17
= 16-29
-13.
f(x)= 2x^3 -3x^2-17
f(2)= 2x2 ^3 - 3x2^2 -17
16-12-17
= 16-29
-13.
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