show that (x-2) is
a factor of x 3-42²-28+20
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Solution:
Let p(x)=x3-42^2-28+20 g(x)=x+1
The zero of g(x)= -2
Then p(-2)=(-2)3-42^2-28+20
=(-6)-17654-28+20
=(-6)-17626+20
=(-6)-17606
=0
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