Question

show that (x-2) is a factor of x^3-6x^2+12x-8

Answer 1

x-2 = 0 => x = 2
f(x) => x^3 - 6x^2 + 12x - 8 = 0
f(2) => 2^3 - 6×2^2 + 12×2 - 8 = 0
=> 8 - 24 + 24 - 8 = 0
=> 0 = 0
Since LHS = RHS = 0....Hence proved that (x-2) is the factor of f(x)....

hope it helps u...☺

Answer 2

$\blue{\huge{\boxed{\star\: Solution \: \star}}}$


====>
$\boxed{x - 2 = 0}$

===> x = 2

$\red{put \: x \: in \: equation}$


===>
${2}^{3} - 6(2) {}^{2} + 12(2) - 8$

===> 8 - 24 + 24 -8

$\cancel{8 - 24 + 24 - 8}$

==>
$\red{ \boxed{ \underline{the \: remainder \: is \: 0}}}$

===> Hence (x-2) is factor of given expression