Question

show that (x-2) is a factor of (x^3-8)

Answer 1

g(x)=x-2 
0=x-2 
so x= 2 
then put the value of x in x^3-8 
so 2^3-8 
then 8-8 =o 
so (x-2) is the factor of x^3-8 

Answer 2

p(x)=x^3-8
g(x)=x-2
0=x-2
x=2
by putting the value of x=2
p(x)=x^3-8
p(2)=2^3-8
=8-8
=0
hence proved