Question

show that (x +2) is a factor of x^4 - x ^2 -12 ​

Answer 1

Step-by-step explanation:

according to factor theorum

g(x)=x⁴-x²-12

f(x)=x+2

x+2=0

x=-2

g(-2)=(-2)⁴-(-2)²-12

g(-2)=16-4-12

g(-2)=0

Answer 2

Answer:

Hi chinky

Here's your answer

Step-by-step explanation:

First we find zeros of the polynomial

x^4-x^2-12

so'

x+2=0

x=0-2

x=-2

then we substitute the value of x in the polynomial x^4-x^2-12

f(x)=x^4-x^2-12

f(-2)=(-2)^4-(-2)^2-12

f(-2)=(16)-(4)-12

f(-2)=16-4-12

f(-2)=12-12

f(-2)=0

so'

f(-2)=0 if the remainder is 0 the polynomial (........) is a factor of (......).

(x+2) is a factor of (x^4-x^2-12)

Chinky hope it helps to you plz mark me brainliest