Question

Show that (x+2) is a factor of (x5+32).

Answer 1

Answer:

given, p(x) = x^5 + 32

Zero of x+2 --

x+2 = 0

x = -2

To show x+2 is a factor of (x^5 + 32), put x = -2 in the given polynomial and if p(x) will be equal to zero after putting x = -2 then it would show that x+2 is the factor of p(x)

we get --

-2^5 + 32 = 0

-32 + 32 = 0

0 = 0

Since,after putting x = -2,we got zero,Therefore

x + 2 is the factor of p(x)

Step-by-step explanation:

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