Question

show that x-2 is a factor p(x)=x^3-12x^2+44x-48​

Answer 1

Answer:

g(x)=x-2=0

=x=2

p(x)=x^3-12x^2+44x-48

p(2)=2^3 -12×2^2+44×2 -48

=8-12×4+88-48

=8-48+88-48

=-40+40

=0

That means x-2 is the factor of

x^3-12x^2+44x-48

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Answer 2

Step-by-step explanation:

To prove..p (x) = x^3-12^2+44x-48

x-2 is the factor means its a zero of p (x) that means

x-2=0

x=2

Substitute the value of x=2 in p (x)

Now,

x^3-12x^2+44x-48

》2^3- 12×2^2+44×2-48

》8-12×4+88-48

》8-48+88-48

》96-96

》0

As the value is equal to 0 it is proved that x-2 is the factor of p (x).