Question

Show that X=2 is a root of the polynomial f(X) =x^3-6x^2+11-6

Answer 1

Answer:

F(x) = 8-24+11-6

= - 11

Step-by-step explanation:

Hope it is useful for you

Answer 2

Answer:

Step-by-step explanation:

F(x)= x^3-6x^2 +11-6

F(2)=2^3-6×2^2+11-6

F(2)=8-24+11-6

F(2)=-11

HOPE THIS WILL HELP YOU