Question

show that x-2, x+3 and x-7 are the factors of x³-6x²-13x+42​

Answer 1

Step-by-step explanation:

show that x-2, x+3 and x-7 are the factors of x³-6x²-13x+42

Answer 2

By converse of Factor theorem, we know that,

If (x-a) is the factor of the polynomial p(x) then p(a) must be zero.

Here, if (x-2) is the factor of the polynomial p(x) = x³ - 6x² - 13x + 42

then, p(2) = 0

similarly, (x+3) and (x-7) will be the factors of p(x) if

p(-3) and p(7) will be zero.

CALCULATE IT AND SHOW IT.