Question

Show that x=2 y=3 satisfy the linear equation 3x-4y+6=0

Answer 1

Putting x=2 , y=3
=3x-4y+6=0
=3×2-4×3+6=0
=6-12+6=0
=12-12=0
=0=0

Answer 2

Heyaaa mate

The answer is

X = 2 , Y = 3

$3x - 4y + 6 = 0$

After substituting value

$3(2) - 4(3) + 6 = 0$

$6 - 12 + 6 = 0$

$- 6 + 6 = 0$

$0 = 0$

Hence,

$\huge\boxed{LHS=RHS}$

Hope it helps you

Thanks