Question

show that x=2is a zero of 2x3+x2-7x-6​

Answer 1

Answer:

x=2 is a zero of 2x^3 + x^2 - 7x - 6

Step-by-step explanation:

Given,

p(x) = 2x^3 + x^2 - 7x - 6

Put x = 2

p(2) = 2(2)^3 + (2)^2 - 7(2) - 6

p(2) = 16 + 4 - 14 - 6

p(2) = 20 - 20 = 0

Since,

p(2) = 0.

Hence, x=2 is a zero of p(x).

Proved....

Hope it helps you.......

Answer 2

ANSWER:

• Yes , 2 is the zero of the given polynomial.

GIVEN:

• P(x) = 2x³+x²-7x-6

TO FIND:

• Whether 2 is a Zero of polynomial P(x).

SOLUTION:

=> P(x) = 2x³+x²-7x-6

Let us check whether 2 is the zero of P(x)

Putting x = 2 in P(x)

=> P(2) = 2(2)³+(2)²-7(2)-6

=> P(2) = 16+4-14-6

=> P(2) = 20-20

=> P(2) = 0

Yes , 2 is the Zero of the given polynomial.

NOTE:

Some important formulas:

(a+b)² = a²+b²+2ab

(a-b)² = a²+b²-2ab

(a+b)(a-b) = a²-b²

(a+b)³ = a³+b³+3ab(a+b)

(a-b)³ = a³-b³-3ab(a-b)

a³+b³ = (a+b)(a²+b²-ab)

a³-b³ = (a-b)(a²+b²+ab)

(a+b)² = (a-b)²+4ab

(a-b)² = (a+b)²-4ab