Math, asked by aayushbarate, 11 months ago

Show that x = 3 and y = 2 is not a solution of the
system of simultaneous linear equations 3x + 4y
= 17 and 4x – 3y = 12.

Answers

Answered by soniriya213
2

Answer:

ur ans is above in image......

Attachments:
Answered by ss3566021
4

Answer:

solution : solve the equations

3x + 4y = 17. ... (1)

and 4x - 3y = 12. . .(2)

multiplying 3 with equation (1) and 4 with

equation (2) and adding both equations. i.e., 3(3x + 4y) + 4(4x - 3y) = 3× 17 + 4 x 12

- 9x + 12y + 16x - 12y = 51 + 48 = 99

= 25x = 99

X= 99/25

now putting x = 99/25 in equation (2) we get,

4(99/25) - 3y = 12

- 396/25 - 12 = 3y

→ 96/25 = 3y

y = 32/25

here x = 99/25 is not equal to 3 and у 32/25 is not equal to 2.

Therefore x = 3 and y = 2 is not a solution of the system of simultaneous linear equations 3x + 4y = 17 and 4x - 3y = 12.

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