Question

show that x=3 and y=4 is not a solution of following pair pf linear equations 5x -2y =7, x -2y =10​

Answer 1

Step-by-step explanation:

x -2y =10

5x -2y =7

substitute given values in these equations

x -2y =10

3-2(4)= 10

3- 8 = 10

-5 ≠ 10

Thus , LHS≠RHS

x=3 and y=4 are not the solution for this equation

5x -2y =7

5(3)-2(4)=7

15-8=7

7=7

Thus, LHS=RHS

x=3 and y=4 are the solution for this equation

HOPE THIS WILL HELP YOU

Answer 2

Answer:

let,

5x - 2y = 7 ............... equation 1

and, x - 2y = 10 ................equestion 2

now , putting x=3 and y=4 in equation 1

> 5(3) - 2(4) = 7

> 15 - 8 = 7

> 7=7

hence, L.H.S. = R.H.S.

therefore,

value of x and y is the solution of equation 1

Now ,putting the value of x and y in equation 2

> (3) - 2(4) = 10

> 3 - 8 = 10

> -5 = 10

hence, L.H.S. = R.H.S.

therefore,

value of x and y is not the solution of equation 2

${ \: thank \: you}$