Question

show that x+3 is a factor of 69+11x-x^2+x^3

Answer 1

Let us assume (x+3) to be a factor of the given polynomial.

Hence substitute the value of 'X' in the polynomial.

{proof is there in the attachment}
HOPE IT HELPS YOU

Answer 2

Step-by-step explanation:

We need to show that (x+3) is a factor of $69+11x-x^2+x^3$. If it is the factor of (x+3), then f(-3) should be equal to 0.

Let $f(x)=69+11x-x^2+x^3$

Put x = -3 in above function

$f(-3)=69+11\left(-3\right)-\left(-3\right)^{2}+\left(-3\right)^{3}\\\\f(-3)=0$

It means that (x+3) is a factor of  $69+11x-x^2+x^3$.

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Factors

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