Show that (x+3) is a factor of p(x) = 69+11x-x^2+x^3.
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Hii Mate Here is Your Answer,
To Prove : x+3 is a factor of p(x) = 69+11x-x^2+x^3
We can easily prove it by using Factor Theorem.
x+3 is factor means its a zero of p(x) that means
x+3 = 0
x = -3
Substitute the value of X= -3 in p(x)
69+11x - x^2 + x^3
》 69 + 11 × -3 - (-3)^2 + (-3)^3
》 69 -33 -9 - 27
》 69-69
》 0
As the value is equals to 0 it is proved that
x+3 is a factor of p(x).
☆☆☆ HOPE THIS HELPS YOU A LOT ☆☆☆☆
To Prove : x+3 is a factor of p(x) = 69+11x-x^2+x^3
We can easily prove it by using Factor Theorem.
x+3 is factor means its a zero of p(x) that means
x+3 = 0
x = -3
Substitute the value of X= -3 in p(x)
69+11x - x^2 + x^3
》 69 + 11 × -3 - (-3)^2 + (-3)^3
》 69 -33 -9 - 27
》 69-69
》 0
As the value is equals to 0 it is proved that
x+3 is a factor of p(x).
☆☆☆ HOPE THIS HELPS YOU A LOT ☆☆☆☆
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