Question

show that x -3 is a factor of p (x) is equals to 3 x cube - x^ - 3 x + 1 and hence factorise P(X)​

Answer 1

Step-by-step explanation:

Solution:-

if x-3 is a factor of p(x)

then

x-3=0

${:}\longrightarrow$x=3

${:}\longrightarrow$$p (3)=3({3)}^{3}-{3}^{(-3({3)}+1)}$

${:}\longrightarrow$$3×9-{3}^{0+1}$

${:}\longrightarrow$$27-{3}^{1}$

${:}\longrightarrow$$27-3$

${:}\longrightarrow$${\underline{\boxed{\bf {24}}}}$