Question

show that (x-3) is a factor of p(x)=x³-3x²+4x-12​

Answer 1

Answer:

Step-by-step explanation:

p(x)=x³-3x²+4x-12

g(x)=x-3

p(3)=(3)³-3*(3)²+4*3-12

     =27-3*9+12-12

     =27-27

     =0

∴(x-3) is a factor of p(x)

Answer 2

put x-3=0 then x=3

then put the value of x in the equation and u will get the value=0