Question

show that (x-3) is a factor of polynomial x^3-4x^2+x+6​

Answer 1

Step-by-step explanation:

given (x-3) is a factor

so x-3=0

and x=3

put x=3 in polynomial x^3-4x^2+x+6

3³ - 4*3² +3 +6

27 - 36 +3+6 =0

by putting x=3 we get polynomial value is 0

so (x-3) is a factor of polynomial x^3-4x^2+x+6