show that x+3 is a factor of the following p(x)=x^4+x^3-7x^2-x+6
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Answer:
show that x+3 is a factor of the following p(x)=x^4+x^3-7x^2-x+6
Step-by-step explanation:
sorry........................................
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Answer:
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Step-by-step explanation:
x+3=0
x=-3
(-3)⁴+(-3)³-7(-3)²-(-3)+6
81-27-63+3+6
81-90+9
0
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