Math, asked by Rythm14, 1 year ago

Show that ( x + 3 ) is a factor of
x^3 + x^2 - 4x + 6

Answers

Answered by Anonymous
203

\huge{\underline{\underline{\tt{\purple{Answer}}}}}\:

Given is that . Prove that x + 3 is a factor of polynomial x^3\:+\:x^2\:-\:4x\:+\:6

If x + 3 would be a factor of this given polynomial then ,

g (x) = x + 3 = 0

x = -3

Substituting the value -3 of the variable x in the polynomial x^3\:+\:x^2\:-\:4x\:+\:6

\implies\:p(x)\:=\:x^3\:+\:x^2\:-\:4x\:+\:6

\implies\:p(x)\:=\:(-3)^3\:+\:(-3)^2\:-\:4(-3)\:+\:6\:=\:0

\implies\:p(x)\:=\:-\:27\:+\:9\:+\:12\:+\:6\:=\:0

\implies\:p(x)\:=\:-\:27\:+27\:=\:0

\implies\:p(x)\:=\:0\:=\:0

Hence , LHS = RHS

Thus proved that x+ 3 is a factor of the polynomial x^3\:+\:x^2\:-\:4x\:+\:6

\huge\star\:\:{\orange{\underline{\pink{\mathbf{Basics}}}}}

While solving any question related to polynomial use four-step strategy .

  • Simplify both sides if you think it's required

  • write the equation in standard form

  • Factorise the equation

  • Zero - Product Principle or LHS = RHS
Answered by itzheatless
1

Step-by-step explanation:

Given is that . Prove that x + 3 is a factor of polynomial x^3\:+\:x^2\:-\:4x\:+\:6x

3

+x

2

−4x+6

If x + 3 would be a factor of this given polynomial then ,

g (x) = x + 3 = 0

x = -3

Substituting the value -3 of the variable x in the polynomial x^3\:+\:x^2\:-\:4x\:+\:6x

3

+x

2

−4x+6

\implies\:p(x)\:=\:x^3\:+\:x^2\:-\:4x\:+\:6⟹p(x)=x

3

+x

2

−4x+6

\implies\:p(x)\:=\:(-3)^3\:+\:(-3)^2\:-\:4(-3)\:+\:6\:=\:0⟹p(x)=(−3)

3

+(−3)

2

−4(−3)+6=0

\implies\:p(x)\:=\:-\:27\:+\:9\:+\:12\:+\:6\:=\:0⟹p(x)=−27+9+12+6=0

\implies\:p(x)\:=\:-\:27\:+27\:=\:0⟹p(x)=−27+27=0

\implies\:p(x)\:=\:0\:=\:0⟹p(x)=0=0

Hence , LHS = RHS

Thus proved that x+ 3 is a factor of the polynomial x^3\:+\:x^2\:-\:4x\:+\:6x

3

+x

2

−4x+6

\huge\star\:\:{\orange{\underline{\pink{\mathbf{Basics}}}}}⋆

Basics

While solving any question related to polynomial use four-step strategy .

●Simplify both sides if you think it's required

●write the equation in standard form

●Factorise the equation

●Zero - Product Principle or LHS = RHS

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