Show that ( x + 3 ) is a factor of
x^3 + x^2 - 4x + 6
Answers
Given is that . Prove that x + 3 is a factor of polynomial
If x + 3 would be a factor of this given polynomial then ,
g (x) = x + 3 = 0
x = -3
Substituting the value -3 of the variable x in the polynomial
Hence , LHS = RHS
Thus proved that x+ 3 is a factor of the polynomial
While solving any question related to polynomial use four-step strategy .
- Simplify both sides if you think it's required
- write the equation in standard form
- Factorise the equation
- Zero - Product Principle or LHS = RHS
Step-by-step explanation:
Given is that . Prove that x + 3 is a factor of polynomial x^3\:+\:x^2\:-\:4x\:+\:6x
3
+x
2
−4x+6
If x + 3 would be a factor of this given polynomial then ,
g (x) = x + 3 = 0
x = -3
Substituting the value -3 of the variable x in the polynomial x^3\:+\:x^2\:-\:4x\:+\:6x
3
+x
2
−4x+6
\implies\:p(x)\:=\:x^3\:+\:x^2\:-\:4x\:+\:6⟹p(x)=x
3
+x
2
−4x+6
\implies\:p(x)\:=\:(-3)^3\:+\:(-3)^2\:-\:4(-3)\:+\:6\:=\:0⟹p(x)=(−3)
3
+(−3)
2
−4(−3)+6=0
\implies\:p(x)\:=\:-\:27\:+\:9\:+\:12\:+\:6\:=\:0⟹p(x)=−27+9+12+6=0
\implies\:p(x)\:=\:-\:27\:+27\:=\:0⟹p(x)=−27+27=0
\implies\:p(x)\:=\:0\:=\:0⟹p(x)=0=0
Hence , LHS = RHS
Thus proved that x+ 3 is a factor of the polynomial x^3\:+\:x^2\:-\:4x\:+\:6x
3
+x
2
−4x+6
\huge\star\:\:{\orange{\underline{\pink{\mathbf{Basics}}}}}⋆
Basics
While solving any question related to polynomial use four-step strategy .
●Simplify both sides if you think it's required
●write the equation in standard form
●Factorise the equation
●Zero - Product Principle or LHS = RHS