Show that x-3 is a factor of x3 -3x2 +4x -12
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Answer:
By long division method the given polynomial can be simplified to \frac{x^3-4x^2+x+6}{x-3}=x^2-x-2
x−3
x
3
−4x
2
+x+6
=x
2
−x−2
Step-by-step explanation:
Given that x-3 is a factor of the polynomial 6+x-4x^2+x^36+x−4x
2
+x
3
Rewritting the given polynomial as x^3-4x^2+x+6x
3
−4x
2
+x+6
To Solve the given polynomial by long division method :
x^2-x-2x
2
−x−2
_______________
x-3 )x^3-4x^2+x+6x
3
−4x
2
+x+6
x^3-3x^2x
3
−3x
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