Show that (x-3) is a factor of x⁴-3.Show that (x-3) is a factor of x⁴-3.
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=g(x) = x-3
=x-3 = 0
=x = 3
=Putting x = 3 in p(x) = x⁴- 3
=p(3) = (3)⁴- 3
= 81 - 3
= 79.
≈No, g(x) = x-3 is not a factor of p(x) = x⁴-3.
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