Show that x=-3 is a solution of 2x²+5x-3=0
laxmikant6:
yess
by factorization method
2x^2 + 5x -3 = 0
2x^2 + 6x -x -3 = 0
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I have give tje prove below
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by factorisation method
2x^2 + 6x -x - 3 = 0 , 2x (x+3) - 1 (x+3) = 0 , (2x-1) (x+3) = 0 , x = 1/2 or x = -3 therefore , -3 is the solution of 2x^2 + 5x -3 = 0
kiska hai
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Answer:
x = - 3 or x = - 1 / 2 are the roots of the given quadratic equation.
Step-by-step-explanation:
The given quadratic equation is
2x² - 5x - 3 = 0
∴ 2x² - 5x - 3 = 0
➜ 2x² - 6x + x - 3 = 0
➜ 2x ( x - 3 ) + 1 ( x - 3 ) = 0
➜ ( x - 3 ) ( 2x + 1 ) = 0
➜ ( x - 3 ) = 0 or ( 2x + 1 ) = 0
➜ x - 3 = 0 or 2x + 1 = 0
➜ x = 3 or 2x = - 1
➜ x = - 3 or x = - 1 / 2
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