show that x=-3 is a solution of x2+6+9=0
Answers
Answered by
3
These is an attachment to your question thanks
Attachments:
Answered by
11
The equations you gave are:
x = -3
x^2 + 6x + 9 = 0
Factor the trinomial:
(x+3)(x+3) = 0
Since this is a perfect square, re-write it as such:
(x+3)^2 = 0
there’s only one valid solution for x that will make this a true statement, and that is x = -3:
(x+3)^2 = 0
(-3 + 3) ^2 = 0
(0)^2 = 0
0 = 0
Even in its factored, expanded form:
(x+3)(x+3) = 0
x = -3
(-3 + 3)(-3 + 3) = 0
0*0 = 0
0 = 0
And in the original equation:
-3^2 + 6*-3 + 9 = 0
9 - 18 + 9 = 0
-9 + 9 = 0
0 = 0
PLEASE MARK AS BRAINLIEST ANSWER
Similar questions