Question

show that x=√3 is solution of x^2-3√3x+6=0​

Answer 1

Answer:

x^2-3√3x+6=0

√3^2-3√3×√3+6=0

3-9+6=0

-9+9=0

0=0

LHS = RHS

HENCE,PROVED

Answer 2

Answer:

Step-by-step explanation:

let p(x)=x^2-3sqrt(3)x+6=0

now p(sqrt(3))

=((sqrt(3)^2-3sqrt(3)(sqrt(3))+6)

=(3-3*3+6)

=3-9+6

=9-9

=0

so when we substitute the value then the result must be zero

so sqr(3) is the solution of p(x)