Question

show that x=3 is the 0 of the polynomial x^3-6x^2+11x-6 Pls Help

Answer 1

Answer:

Step-by-step explanation:

GIVEN :

X = 3 IS A ZERO OF THE GIVEN POLYNOMIAL.

LET THE POLYNOMIAL BE EXPRESSED AS P (X).

P(X) = X³- 6 X²+11 X -6

SUBSTITUTING X = 3.

P(X) = 3³-6*3²+11*3-6

       = 27-54+33-6

       = 60-60

       = 0.

THEREFORE X = 3 IS A ZERO OF THE GIVEN POLYNOMIAL.

HENCE PROVED.

HOPE THIS HELPS.

Answer 2

replace the x with 3

p(x)=x^3-6x^2+11x-6

p(3)=3^3-6*3^2+11*3-6

27-36+33-6

=18

Means that x=3 is not the zero of the polynomial of x^3-6x^2+11x-6