show that x=4 and y=1 is the solution of linear equation 2x+3y = 11 and x-2y =2
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(2x+3y=11)×2
(x-2y=2)×3
4x+6y=22
+3x-6y=6
= 7x=28
x=28//7=4
y=1
(x-2y=2)×3
4x+6y=22
+3x-6y=6
= 7x=28
x=28//7=4
y=1
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