Question

Show that x = 4 and y = 2 is a solution of the system of simultaneous linear equations 3x - 2y = 8, x + y = 6.

Answer 1

Given :

• x = 4 and y = 2

To Prove :

• x = 4 and y = 2 is a solution of the system of simultaneous linear equations 3x - 2y = 8, x + y = 6.

Step-by-step explanation :

The given equations are

3x - 2y = 8 .... (i)

x + y = 6 ..... (ii)

Putting x = 4 and y = 2 in (i), we get

L.H.S. = (3 x 4-2 x 2) = 8 = R.H.S

Putting x = 4 and y = 2 in (ii), we get

L.H.S. = (4 + 2) = 6 = R.H.S.

Thus, x = 4 and y = 2 satisfies both the equations of the given system.

So, x = 4, y = 2 is a solution of the given system.

Answer 2

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☆$\small\green {\sf{Answer }}$☆

x = 4 and y = 2 is a solution of the system of simultaneous linear equations 3x - 2y = 8, x + y = 6.

The given equations are

3x - 2y = 8 .... (i)

x + y = 6 ..... (ii)

Putting x = 4 and y = 2 in (i), we get

L.H.S. = (3 x 4-2 x 2) = 8 = R.H.S

Putting x = 4 and y = 2 in (ii), we get

L.H.S. = (4 + 2) = 6 = R.H.S.

Thus, x = 4 and y = 2 satisfies both the equations of the given system.

So, x = 4, y = 2 is a solution of the given system.