Question

show that (x+4) ,(x-3) are factors of xcube-6x square-19x+84 don't spam​

Answer 1

Answer:

Equation is (x+4)(x-3)(x-7)(x+4)(x−3)(x−7)

=(x^2-3x+4x-12)(x-7)=(x

2

−3x+4x−12)(x−7)

=(x^2+x-12)(x-7)=(x

2

+x−12)(x−7)

=x^3+x^2-12x-7x^2-7x+84=x

3

+x

2

−12x−7x

2

−7x+84

=x^3-6x^2-19x+84=x

3

−6x

2

−19x+84