show that x-5 is a factor of the polynomial f(x)=x^3+x^2+3x+115.
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Answers
Answer:
(x - 5) is not the factor of the polynomial x³ + x² + 3x + 115.
Step-by-step explanation:
To check : (x - 5) is a factor of polynomial (x³ + x² + 3x + 115.)
To show the above, simply plug out the value of x from (x - 5), and then substitute it in the polynomial.
If the result comes 0, it means that (x - 5) is a factor. Here we go;
- x - 5 = 0
- x = 5
Putting the value of x in the above polynomial.
⇒ x³ + x² + 3x + 115
⇒ 5³ + 5² + 3 * 5 + 115
⇒ 125 + 25 + 15 + 115
⇒ 280
Since remainder is not zero. Hence, (x - 5) is not the factor of the polynomial (x³ + x² + 3x + 115).
f(x) = x³ + x² + 3x + 115
x - 5 is the factor of the above polynomial.
____________ [GIVEN]
=> x - 5 = 0
=> x = 5
Put the value of x in above polynomial. If the remainder came zero (0) then x - 5 is the factor of the polynomial x³ + x² + 3x + 115
=> (5)³ + (5)² + 3(5) + 115
=> 125 + 25 + 15 + 115
=> 280
Then remainder came is 280 which is not 0.
_____________________________
So, x - 5 is not a factor of the polynomial x³ + x² + 3x + 115
___________ [ANSWER]