Show that (x-5) is a factor of x³-3x²-4x-30 by Remainder theorem
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Answered by
21
Simple x=5
then in place of x put 5
then you get
5^3-3(5)^2-4(5)-30
after solving this you will get
0
then it is the factor of the given polynomial
then in place of x put 5
then you get
5^3-3(5)^2-4(5)-30
after solving this you will get
0
then it is the factor of the given polynomial
Answered by
23
we can prove this by dividing the polynomial by x-5
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