show that (x^a+b)^a-b×(x^b+c)^b-c×(x^c+a)^c-a. =1
anyone pls help me
Answers
Answered by
1
(xa+b)a-b .(xb+c)b-c. (xc+a)c-a
= x(a+b)(a-b). x(b+c)(b-c) .x(c+a)(c-a)
= x0
Answered by
0
(x
a+b
)
a−b
.(x
b+c
)
b−c
.(x
c+a
)
c−a
⇒(x
(a+b)⋅(a−b)
).(x
(b+c)⋅(b−c)
).(x
(c+a)⋅(c−a)
)
⇒(x
a
2
+ab−ab−b
2
).(x
b
2
+bc−bc−c
2
).(x
c
2
+ac−ac−a
2
)
⇒(x
a
2
−b
2
).(x
b
2
−c
2
).(x
c
2
−a
2
)
⇒(x
- a
2
−b
2
+b
2
−c
2
+c
2
−a
2
)
⇒x
0
∵a
0
=1
∴x
0
=1
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