Question

show that
(x^a-b)^a+b (x^b-c) (x^c-d)^c+a=1​

Answer 1

Answer:

${x}^{ ({a - b})^{(a + b)} } \times {x}^{ {(b - c)}^{(b + c)} } \times {x}^{ ({c - a})^{(c + a)} } = 1 \\ {x}^{ {a} ^{2} - {b}^{2} } \times {x}^{ {b}^{2} - {c}^{2} } \times {x}^{ {c}^{2} - {a}^{2} } = 1 \\ {x}^{{a}^{2} - {b}^{2} + {b}^{2} - {c}^{2} + {c}^{2} - {a}^{2} } \: = 1 \\ {x}^{0} = 1$