Question

Show that x+a is a factor of x^m - a^m for any even integer m​

Answer 1

Step-by-step explanation:

x+a=0

x= -a

put the value of x in eq

x^m-a^m

= (-a)^m-a^m

= (-1)^m×a^m-a^m

coz m is even integer. so (-1)^m = 1

so 1×a^m-a^m

=a^m-a^m

=0