Show that: (x^a²+b²/x^ab)a+b(x^b²+c²/x^bc) b+c(x^c²+a²/x^ac)a+c =x²(a³+b³+c³)
Answers
Answered by
1
Step-by-step explanation:
Given,
(
x
b
x
a
)
a
2
+ab+b
2
×(
x
c
x
b
)
b
2
+bc+c
2
×(
x
a
x
c
)
c
2
+ca+a
2
=(x
a−b
)
a
2
+ab+b
2
×(x
b−c
)
b
2
+bc+c
2
×(x
c−a
)
c
2
+ca+a
2
=x
a
3
+a
2
b+ab
2
−a
2
b−ab
2
−b
3
×x
b
3
+b
2
c+bc
2
−cb
2
−bc
2
−c
3
×x
c
3
+c
2
a+ca
2
−c
2
a−ca
2
−a
3
=x
a
3
−b
3
×x
b
3
−c
3
×x
c
3
−a
3
=x
a
3
−b
3
+b
3
−c
3
+c
3
−a
3
=x
0
=1 [henceproved]
verified_toppr
Answered by
1
ANSWER : I hope this will help
Attachments:
Similar questions