Question

show that x is irrational,if:
(i)
$x ^2 = 6$
(ii)
$x ^2 = 0.009$
(iii)
$x ^2 = 27$
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Answer 1

Answer:

${x}^{2} = 6 \\ x = \sqrt{3} \\ \\ x^{2} = 0.009 \\ x = 0.09 \\ \\ {x}^{2} = 27 \\ x = 3 \sqrt{3}$

Answer 2

1.x²=6

this no is non-termenating number

so it is irrational number

2.x²=0.009

x=0.3

3.x²=276

this no is non-termenating number

so it is irrational number