Question

Show that x ki power 3 + 2x + 7 has no real zeroes ​

Answer 1

as we know that for no real value
${b}^{2} - 4ac > 0$
now in equation
$3 {x}^{2} + 2x + 7$
a= 3
b= 2
c=7
so
${b}^{2} - 4ac$
=
${2}^{2} - 4(3)(7)$
=4- 84
=-80
which is less than 0