show that x minus 1 is a factor of the polynomial x cube minus 13 x square + 32 X - 20
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1
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Step-by-step explanation:
let,
g(x)= x+1 and ... (1) and g(x)= 0
f(x)= x³-13x²+32x-20 ...(2)
from (1) we know, x-1= 0
therefore, x=1
substituting x=1 in f(x),
f(1)= (1)³ - 13(1)²+32*1-20
= 1 - 13 + 32- 20
= -12+12
= 0
since f(1)=0 we know that (x-1) is a factor of f(x).
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