Show that x minus 3 is a factor of the polynomial x cube minus 3 X square + 4 x minus 12
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Answer:
g(x) = x³ - 3x² + 4x - 12
q(x) = x - 3
=> x - 3 = 0
=> x = 3
g(3) = 3³ - 3(3)² + 4(3) - 12
= 27 - 27 + 12 - 12
= 0
Hence, q(x) = (x - 3) is a factor of the polynomial g(x) = x³ - 3x + 4x - 12
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