Math, asked by annmery37, 4 months ago

Show that :-
(x-y) (x+y) + (y-z) (y+z) + (z-x) (z+x) = 0​

Answers

Answered by ritikrajput496
4

Answer:

x^2-Y^2+Y^2-Z^2+Z^2-X^2=0

all are cancel together

become zero

Answered by Anonymous
6

Answer:

Mark me as brainliest

Step-by-step explanation:

(x-y) (x+y) + (y-z) (y+z) + (z-x) (z+x)

(x²+xy-xy-y²+y²+yz-yz-z²+z²+xz-xz-x²)

= 0

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