Show that :-
(x-y) (x+y) + (y-z) (y+z) + (z-x) (z+x) = 0
Answers
Answered by
4
Answer:
x^2-Y^2+Y^2-Z^2+Z^2-X^2=0
all are cancel together
become zero
Answered by
6
Answer:
Mark me as brainliest
Step-by-step explanation:
(x-y) (x+y) + (y-z) (y+z) + (z-x) (z+x)
(x²+xy-xy-y²+y²+yz-yz-z²+z²+xz-xz-x²)
= 0
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