Question

. Show that (x+y)(x-y) + (y+z)(y-z) + (z+x)(z-x)=0

Answer 1

Step-by-step explanation:

LHS

(x+y)(x-y) + (y+z)(y-z) + (z+x)(z-x)

=> (x²-y²)+(y²-z²)+(z²-x²)

=>x²-x²-y²+y²-z²+z²

=> 0 =0= RHS

Answer 2

Answer:

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Step-by-step explanation:

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