show that
(x-y) (x+y) + (y-z) (y+z) + (z-x) (z+x) = 0
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Answer:
show that
(x-y) (x+y) + (y-z) (y+z) + (z-x) (z+x) = 0
Step-by-step explanation:
show that
(x-y) (x+y) + (y-z) (y+z) + (z-x) (z+x) = 0
Answered by
0
0 is the answer
pls make me brainliest
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