Question

show that
(x-y) (x+y) + (y-z) (y+z) + (z-x) (z+x) = 0 ​

Answer 1

Step-by-step explanation:

Answer

Given that,

xy(x−y)+yz(y−z)+zx(z−x)

=(x×x×y)−(x×y×y)+(y×y×z)−(y×z×z)+(z×z×x)−(z×x×x)