show that |x+y, z, z-x| |y+z, x, x-y| |z+x, y, y-z| =x^3+y^3 +z^3-3xyz
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Answer:
x+y)
3
=(−z)
3
⟹x
3
+y
3
+3x
2
y+3xy
2
=−z
3
⟹x
3
+y
3
+3xy(x+y)=−z
3
⟹x
3
+y
3
+3xy(−z)=−z
3
⟹x
3
+y
3
−3xyz=−z
3
⟹x
3
+y
3
+z
3
=3xyz
Answered by
0
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