Question

show that( x2+1)2-X2 =0HAS NO REAL ROOTS​

Answer 1

Answer:

fyofkgcmhzgjchzbcnfxhzgmxngcmgzgncgmx.v

Step-by-step explanation:

Answer 2

Answer:

I’ll renotate with z to acknowledge complex solutions,

(z2+1)2−z2=0

That’s the difference of two squares so factors as

(z2−z+1)(z2+z+1)=0

Applying the quadratic formula to each factor gives

z=12(1±i3–√) or z=12(−1±i3–√)

We can write that as

z=12(±1±i3–√)

Four roots, none real.