Show that x2 + 6x + 10 polynomial has no zero/root .
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on comparing x²+6x+10 with ax²+bx+c
a=1 , b=6 , c=10
discriminate,D= b²-4ac
= 6²-4(1)(10
=36- 40
= -4
by quadratic formula (class 10)
x= -b +√D and x= -b-√D
since √-4 is not a real number
therefore, there are no real zeroes /root
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