Show that (xa+b)a-b ×(xb+c)b-c×(xc+a)c-a = 1
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Answer:
(Xa/x-b)a-b . (xb/x-c)b-c .(xc/x-a)c-a
= (xa+b)a-b , (xb+c)b-c .(xc+a)c-a
= x(a+b)(a-b) . x(b+c)(b-c) .x(c+a)(c-a)
= xo
= 1 = R.H.S
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