Math, asked by anshumanyadav3011, 1 day ago

Show that (xa+b)a-b ×(xb+c)b-c×(xc+a)c-a = 1​

Answers

Answered by kiranveerkaur40
1

Answer:

(Xa/x-b)a-b . (xb/x-c)b-c .(xc/x-a)c-a

= (xa+b)a-b , (xb+c)b-c .(xc+a)c-a

= x(a+b)(a-b) . x(b+c)(b-c) .x(c+a)(c-a)

= xo

= 1 = R.H.S

this is your answer

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Answered by chauhanharendra4
4

Answer:

the answer is attached below try to understand it

Step-by-step explanation:

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