Show that y-1 is a factor of y^20-1 and also y^21-1
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Answer:
According to factor theorem if y-1 is a factor of y^20 - 1 and y^21 - 1 then it's zero y(1)= 0. ... 0. Hence y-1 is a factor of y^20 -1 and y^21 -1.
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For y-1 to be a factor of y^20 - 1 and y^21-1, remainder must be zero.
Using remainder theorem
Let p(y) = p(1) [because y-1 = 0 thus y=1]
p(1) = 1^20-1 = 1-1 = 0
q(y) = 1^21-1 = 1-1 = 0
Thus, y-1 is factor of both p(y) and q(y)
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