Show that y-1 is a factor of y^20 -1 and y^21 -1
Answers
Answered by
81
According to factor theorem if y-1 is a factor of y^20 - 1 and y^21 - 1 then it's zero y(1)= 0.
=) 1^20 - 1
=) 1 - 1
=) 0.
And
=) 1^21 - 1
=) 1 - 1
=) 0.
Hence y-1 is a factor of y^20 -1 and y^21 -1.
Hope it's helpful to u.
=) 1^20 - 1
=) 1 - 1
=) 0.
And
=) 1^21 - 1
=) 1 - 1
=) 0.
Hence y-1 is a factor of y^20 -1 and y^21 -1.
Hope it's helpful to u.
Answered by
50
Hey there ,
We know that ( x-a) is a factor of f(x) then f(a)=0 .
so ,
Here f(y) = y^20-1
g(y ) = y²¹-1
If ( y -1) is a factor of f(y) then f(1) =0
f(1)
= 1^20-1
=0
Hence ( y -1) is a factor of y^20-1
===============-------------==============
If ( y -1) is a factor of g(y) then g(1) =0
g(1)
= 1^21-1
=0
Hence ( y -1) is a factor of y^21 -1
Therefore, ( y-1 ) is a factor of y^20 -1 and y^21 -1
Hope it helped !
We know that ( x-a) is a factor of f(x) then f(a)=0 .
so ,
Here f(y) = y^20-1
g(y ) = y²¹-1
If ( y -1) is a factor of f(y) then f(1) =0
f(1)
= 1^20-1
=0
Hence ( y -1) is a factor of y^20-1
===============-------------==============
If ( y -1) is a factor of g(y) then g(1) =0
g(1)
= 1^21-1
=0
Hence ( y -1) is a factor of y^21 -1
Therefore, ( y-1 ) is a factor of y^20 -1 and y^21 -1
Hope it helped !
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